Base | Representation |
---|---|
bin | 100101000110100111011… |
… | …1010101111110010111001 |
3 | 200001111120110012220101221 |
4 | 1022031032322233302321 |
5 | 1132022133223001241 |
6 | 14502353255312041 |
7 | 1034265062353645 |
oct | 112151672576271 |
9 | 20044513186357 |
10 | 5099450203321 |
11 | 1696734774241 |
12 | 6a438367b621 |
13 | 2acb50a04c16 |
14 | 138b597abc25 |
15 | 8c9ad5585d1 |
hex | 4a34eeafcb9 |
5099450203321 has 2 divisors, whose sum is σ = 5099450203322. Its totient is φ = 5099450203320.
The previous prime is 5099450203303. The next prime is 5099450203339. The reversal of 5099450203321 is 1233020549905.
It is a balanced prime because it is at equal distance from previous prime (5099450203303) and next prime (5099450203339).
It can be written as a sum of positive squares in only one way, i.e., 4641391963321 + 458058240000 = 2154389^2 + 676800^2 .
It is a cyclic number.
It is not a de Polignac number, because 5099450203321 - 211 = 5099450201273 is a prime.
It is not a weakly prime, because it can be changed into another prime (5099450203381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2549725101660 + 2549725101661.
It is an arithmetic number, because the mean of its divisors is an integer number (2549725101661).
Almost surely, 25099450203321 is an apocalyptic number.
It is an amenable number.
5099450203321 is a deficient number, since it is larger than the sum of its proper divisors (1).
5099450203321 is an equidigital number, since it uses as much as digits as its factorization.
5099450203321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 291600, while the sum is 43.
The spelling of 5099450203321 in words is "five trillion, ninety-nine billion, four hundred fifty million, two hundred three thousand, three hundred twenty-one".
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