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5099450203381 is a prime number
BaseRepresentation
bin100101000110100111011…
…1010101111110011110101
3200001111120110012220111011
41022031032322233303311
51132022133223002011
614502353255312221
71034265062354062
oct112151672576365
920044513186434
105099450203381
111696734774296
126a438367b671
132acb50a04c61
14138b597abc69
158c9ad558621
hex4a34eeafcf5

5099450203381 has 2 divisors, whose sum is σ = 5099450203382. Its totient is φ = 5099450203380.

The previous prime is 5099450203363. The next prime is 5099450203409. The reversal of 5099450203381 is 1833020549905.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2594064572100 + 2505385631281 = 1610610^2 + 1582841^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5099450203381 is a prime.

It is a super-2 number, since 2×50994502033812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5099450203321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2549725101690 + 2549725101691.

It is an arithmetic number, because the mean of its divisors is an integer number (2549725101691).

Almost surely, 25099450203381 is an apocalyptic number.

It is an amenable number.

5099450203381 is a deficient number, since it is larger than the sum of its proper divisors (1).

5099450203381 is an equidigital number, since it uses as much as digits as its factorization.

5099450203381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 49.

The spelling of 5099450203381 in words is "five trillion, ninety-nine billion, four hundred fifty million, two hundred three thousand, three hundred eighty-one".