Base | Representation |
---|---|
bin | 100101000110111010111… |
… | …1011001100000011000111 |
3 | 200001120021001122020200112 |
4 | 1022031311323030003013 |
5 | 1132030003241133341 |
6 | 14502542234103235 |
7 | 1034320230036554 |
oct | 112156573140307 |
9 | 20046231566615 |
10 | 5100104630471 |
11 | 1696a40117024 |
12 | 6a452687ab1b |
13 | 2acc26479016 |
14 | 138bbc681a2b |
15 | 8c9eac27aeb |
hex | 4a375ecc0c7 |
5100104630471 has 2 divisors, whose sum is σ = 5100104630472. Its totient is φ = 5100104630470.
The previous prime is 5100104630437. The next prime is 5100104630497. The reversal of 5100104630471 is 1740364010015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5100104630471 - 210 = 5100104629447 is a prime.
It is a super-3 number, since 3×51001046304713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5100104630431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550052315235 + 2550052315236.
It is an arithmetic number, because the mean of its divisors is an integer number (2550052315236).
Almost surely, 25100104630471 is an apocalyptic number.
5100104630471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5100104630471 is an equidigital number, since it uses as much as digits as its factorization.
5100104630471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 5100104630471 its reverse (1740364010015), we get a palindrome (6840468640486).
The spelling of 5100104630471 in words is "five trillion, one hundred billion, one hundred four million, six hundred thirty thousand, four hundred seventy-one".
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