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51004143011 is a prime number
BaseRepresentation
bin101111100000000101…
…010111010110100011
311212122120021220212202
4233200011113112203
51313424030034021
635233031443415
73453634030253
oct574005272643
9155576256782
1051004143011
111a6a3566608
129a7522656b
134a6aaca8a3
14267bc39963
1514d7ae3a0b
hexbe01575a3

51004143011 has 2 divisors, whose sum is σ = 51004143012. Its totient is φ = 51004143010.

The previous prime is 51004142971. The next prime is 51004143031. The reversal of 51004143011 is 11034140015.

It is a happy number.

51004143011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (51004143031) can be obtained adding 51004143011 to its sum of digits (20).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51004143011 - 218 = 51003880867 is a prime.

It is a super-2 number, since 2×510041430112 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51004143031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25502071505 + 25502071506.

It is an arithmetic number, because the mean of its divisors is an integer number (25502071506).

Almost surely, 251004143011 is an apocalyptic number.

51004143011 is a deficient number, since it is larger than the sum of its proper divisors (1).

51004143011 is an equidigital number, since it uses as much as digits as its factorization.

51004143011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 51004143011 its reverse (11034140015), we get a palindrome (62038283026).

The spelling of 51004143011 in words is "fifty-one billion, four million, one hundred forty-three thousand, eleven".