Base | Representation |
---|---|
bin | 100101000111000100001… |
… | …1000111111001110010111 |
3 | 200001121001122120210200211 |
4 | 1022032020120333032113 |
5 | 1132031122043312101 |
6 | 14503033102150251 |
7 | 1034331011231503 |
oct | 112161030771627 |
9 | 20047048523624 |
10 | 5100414432151 |
11 | 1697089a85675 |
12 | 6a45b2582387 |
13 | 2acc756c931c |
14 | 138c0b887303 |
15 | 8ca18020c51 |
hex | 4a38863f397 |
5100414432151 has 2 divisors, whose sum is σ = 5100414432152. Its totient is φ = 5100414432150.
The previous prime is 5100414432149. The next prime is 5100414432163. The reversal of 5100414432151 is 1512344140015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5100414432151 - 21 = 5100414432149 is a prime.
Together with 5100414432149, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5100414432551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550207216075 + 2550207216076.
It is an arithmetic number, because the mean of its divisors is an integer number (2550207216076).
Almost surely, 25100414432151 is an apocalyptic number.
5100414432151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5100414432151 is an equidigital number, since it uses as much as digits as its factorization.
5100414432151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 5100414432151 its reverse (1512344140015), we get a palindrome (6612758572166).
The spelling of 5100414432151 in words is "five trillion, one hundred billion, four hundred fourteen million, four hundred thirty-two thousand, one hundred fifty-one".
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