Base | Representation |
---|---|
bin | 1001100000000001… |
… | …11001111011111101 |
3 | 111011110111210200211 |
4 | 10300000321323331 |
5 | 40421212322343 |
6 | 2202041352421 |
7 | 240252425245 |
oct | 46000717375 |
9 | 14143453624 |
10 | 5100510973 |
11 | 2188118428 |
12 | ba4198711 |
13 | 633920b3c |
14 | 365586b25 |
15 | 1ecbac79d |
hex | 130039efd |
5100510973 has 2 divisors, whose sum is σ = 5100510974. Its totient is φ = 5100510972.
The previous prime is 5100510971. The next prime is 5100510977. The reversal of 5100510973 is 3790150015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3767749924 + 1332761049 = 61382^2 + 36507^2 .
It is a cyclic number.
It is not a de Polignac number, because 5100510973 - 21 = 5100510971 is a prime.
Together with 5100510971, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5100510971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550255486 + 2550255487.
It is an arithmetic number, because the mean of its divisors is an integer number (2550255487).
Almost surely, 25100510973 is an apocalyptic number.
It is an amenable number.
5100510973 is a deficient number, since it is larger than the sum of its proper divisors (1).
5100510973 is an equidigital number, since it uses as much as digits as its factorization.
5100510973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4725, while the sum is 31.
The square root of 5100510973 is about 71417.8617224011. The cubic root of 5100510973 is about 1721.3581049596.
Adding to 5100510973 its reverse (3790150015), we get a palindrome (8890660988).
The spelling of 5100510973 in words is "five billion, one hundred million, five hundred ten thousand, nine hundred seventy-three".
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