Base | Representation |
---|---|
bin | 101111100000011011… |
… | …111010110101001101 |
3 | 11212122222102022021212 |
4 | 233200123322311031 |
5 | 1313432033234001 |
6 | 35233402304205 |
7 | 3454035213656 |
oct | 574033726515 |
9 | 155588368255 |
10 | 51010055501 |
11 | 1a6a6934769 |
12 | 9a771b8065 |
13 | 4a6c0baac2 |
14 | 267c93852d |
15 | 14d83b07bb |
hex | be06fad4d |
51010055501 has 2 divisors, whose sum is σ = 51010055502. Its totient is φ = 51010055500.
The previous prime is 51010055489. The next prime is 51010055543. The reversal of 51010055501 is 10555001015.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50658305476 + 351750025 = 225074^2 + 18755^2 .
It is a cyclic number.
It is not a de Polignac number, because 51010055501 - 214 = 51010039117 is a prime.
It is a super-2 number, since 2×510100555012 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51010055101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505027750 + 25505027751.
It is an arithmetic number, because the mean of its divisors is an integer number (25505027751).
Almost surely, 251010055501 is an apocalyptic number.
It is an amenable number.
51010055501 is a deficient number, since it is larger than the sum of its proper divisors (1).
51010055501 is an equidigital number, since it uses as much as digits as its factorization.
51010055501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 625, while the sum is 23.
Adding to 51010055501 its reverse (10555001015), we get a palindrome (61565056516).
The spelling of 51010055501 in words is "fifty-one billion, ten million, fifty-five thousand, five hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •