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51025345037 is a prime number
BaseRepresentation
bin101111100001010110…
…001111101000001101
311212201001012002120222
4233201112033220031
51313444442020122
635235110121125
73454312163612
oct574126175015
9155631162528
1051025345037
111a704527a47
129a803501a5
134a72312174
142680998509
1514d98d0b42
hexbe158fa0d

51025345037 has 2 divisors, whose sum is σ = 51025345038. Its totient is φ = 51025345036.

The previous prime is 51025344983. The next prime is 51025345039. The reversal of 51025345037 is 73054352015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45475989001 + 5549356036 = 213251^2 + 74494^2 .

It is a cyclic number.

It is not a de Polignac number, because 51025345037 - 28 = 51025344781 is a prime.

It is a super-2 number, since 2×510253450372 (a number of 22 digits) contains 22 as substring.

Together with 51025345039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 51025344988 and 51025345006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51025345039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25512672518 + 25512672519.

It is an arithmetic number, because the mean of its divisors is an integer number (25512672519).

Almost surely, 251025345037 is an apocalyptic number.

It is an amenable number.

51025345037 is a deficient number, since it is larger than the sum of its proper divisors (1).

51025345037 is an equidigital number, since it uses as much as digits as its factorization.

51025345037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63000, while the sum is 35.

The spelling of 51025345037 in words is "fifty-one billion, twenty-five million, three hundred forty-five thousand, thirty-seven".