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5104373 is a prime number
BaseRepresentation
bin10011011110001011110101
3100121022212212
4103132023311
52301314443
6301223205
761246361
oct23361365
910538785
105104373
112976a9a
121861b05
131099451
1496c2a1
156ac618
hex4de2f5

5104373 has 2 divisors, whose sum is σ = 5104374. Its totient is φ = 5104372.

The previous prime is 5104357. The next prime is 5104387. The reversal of 5104373 is 3734015.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3659569 + 1444804 = 1913^2 + 1202^2 .

It is a cyclic number.

It is not a de Polignac number, because 5104373 - 24 = 5104357 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is equal to p355253 and since 5104373 and 355253 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5104303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552186 + 2552187.

It is an arithmetic number, because the mean of its divisors is an integer number (2552187).

Almost surely, 25104373 is an apocalyptic number.

It is an amenable number.

5104373 is a deficient number, since it is larger than the sum of its proper divisors (1).

5104373 is an equidigital number, since it uses as much as digits as its factorization.

5104373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 23.

The square root of 5104373 is about 2259.2859491441. The cubic root of 5104373 is about 172.1792457146.

Adding to 5104373 its reverse (3734015), we get a palindrome (8838388).

The spelling of 5104373 in words is "five million, one hundred four thousand, three hundred seventy-three".