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5105114341 is a prime number
BaseRepresentation
bin1001100000100100…
…11101110011100101
3111011210011200022221
410300102131303211
540423402124331
62202324152341
7240336520165
oct46022356345
914153150287
105105114341
11218a781a68
12ba58386b1
13634873222
143660245a5
151ed2bb711
hex13049dce5

5105114341 has 2 divisors, whose sum is σ = 5105114342. Its totient is φ = 5105114340.

The previous prime is 5105114281. The next prime is 5105114381. The reversal of 5105114341 is 1434115015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4836646116 + 268468225 = 69546^2 + 16385^2 .

It is a cyclic number.

It is not a de Polignac number, because 5105114341 - 27 = 5105114213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5105114381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552557170 + 2552557171.

It is an arithmetic number, because the mean of its divisors is an integer number (2552557171).

Almost surely, 25105114341 is an apocalyptic number.

It is an amenable number.

5105114341 is a deficient number, since it is larger than the sum of its proper divisors (1).

5105114341 is an equidigital number, since it uses as much as digits as its factorization.

5105114341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

The square root of 5105114341 is about 71450.0828620933. The cubic root of 5105114341 is about 1721.8758087842.

Adding to 5105114341 its reverse (1434115015), we get a palindrome (6539229356).

The spelling of 5105114341 in words is "five billion, one hundred five million, one hundred fourteen thousand, three hundred forty-one".