Base | Representation |
---|---|
bin | 10111001110000011010000… |
… | …11100000110100011001101 |
3 | 20200210022121201201112110202 |
4 | 23213001220130012203031 |
5 | 23143033020243142143 |
6 | 300332442211543245 |
7 | 13516662261624365 |
oct | 1347015034064315 |
9 | 220708551645422 |
10 | 51060323412173 |
11 | 152a661a476429 |
12 | 58879babbab25 |
13 | 2264c7745303a |
14 | c8749344d9a5 |
15 | 5d82e220eab8 |
hex | 2e70687068cd |
51060323412173 has 2 divisors, whose sum is σ = 51060323412174. Its totient is φ = 51060323412172.
The previous prime is 51060323412139. The next prime is 51060323412191. The reversal of 51060323412173 is 37121432306015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49664338627849 + 1395984784324 = 7047293^2 + 1181518^2 .
It is a cyclic number.
It is not a de Polignac number, because 51060323412173 - 212 = 51060323408077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51060323412073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25530161706086 + 25530161706087.
It is an arithmetic number, because the mean of its divisors is an integer number (25530161706087).
Almost surely, 251060323412173 is an apocalyptic number.
It is an amenable number.
51060323412173 is a deficient number, since it is larger than the sum of its proper divisors (1).
51060323412173 is an equidigital number, since it uses as much as digits as its factorization.
51060323412173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90720, while the sum is 38.
Adding to 51060323412173 its reverse (37121432306015), we get a palindrome (88181755718188).
The spelling of 51060323412173 in words is "fifty-one trillion, sixty billion, three hundred twenty-three million, four hundred twelve thousand, one hundred seventy-three".
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