Base | Representation |
---|---|
bin | 10111001110000101011101… |
… | …01000101000101100110111 |
3 | 20200210102122210202102102221 |
4 | 23213002232220220230313 |
5 | 23143042423240243103 |
6 | 300333155121543211 |
7 | 13520033412055144 |
oct | 1347025650505467 |
9 | 220712583672387 |
10 | 51061501102903 |
11 | 152a7074224955 |
12 | 58880894a4b07 |
13 | 2265104435c65 |
14 | c87565a133cb |
15 | 5d83607e01bd |
hex | 2e70aea28b37 |
51061501102903 has 2 divisors, whose sum is σ = 51061501102904. Its totient is φ = 51061501102902.
The previous prime is 51061501102897. The next prime is 51061501103029. The reversal of 51061501102903 is 30920110516015.
Together with next prime (51061501103029) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51061501102903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51061501102103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25530750551451 + 25530750551452.
It is an arithmetic number, because the mean of its divisors is an integer number (25530750551452).
Almost surely, 251061501102903 is an apocalyptic number.
51061501102903 is a deficient number, since it is larger than the sum of its proper divisors (1).
51061501102903 is an equidigital number, since it uses as much as digits as its factorization.
51061501102903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 34.
Adding to 51061501102903 its reverse (30920110516015), we get a palindrome (81981611618918).
The spelling of 51061501102903 in words is "fifty-one trillion, sixty-one billion, five hundred one million, one hundred two thousand, nine hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •