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511004439989 is a prime number
BaseRepresentation
bin1110110111110100011…
…11001111010110110101
31210211222210000011222222
413123322033033112311
531333014114034424
61030430250332125
751630111033641
oct7337217172665
91724883004888
10511004439989
111877967590aa
128305242a045
1339258c6b324
141aa3892bc21
15d45bc9ce5e
hex76fa3cf5b5

511004439989 has 2 divisors, whose sum is σ = 511004439990. Its totient is φ = 511004439988.

The previous prime is 511004439941. The next prime is 511004440021. The reversal of 511004439989 is 989934400115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 370810359364 + 140194080625 = 608942^2 + 374425^2 .

It is a cyclic number.

It is not a de Polignac number, because 511004439989 - 220 = 511003391413 is a prime.

It is a super-2 number, since 2×5110044399892 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 511004439989.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511004439389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255502219994 + 255502219995.

It is an arithmetic number, because the mean of its divisors is an integer number (255502219995).

Almost surely, 2511004439989 is an apocalyptic number.

It is an amenable number.

511004439989 is a deficient number, since it is larger than the sum of its proper divisors (1).

511004439989 is an equidigital number, since it uses as much as digits as its factorization.

511004439989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1399680, while the sum is 53.

The spelling of 511004439989 in words is "five hundred eleven billion, four million, four hundred thirty-nine thousand, nine hundred eighty-nine".