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51100531 is a prime number
BaseRepresentation
bin1100001011101…
…1101101110011
310120011011202021
43002323231303
5101040204111
65023132311
71160230066
oct302735563
9116134667
1051100531
1126932649
1215144097
13a782301
146b028dd
154745d71
hex30bbb73

51100531 has 2 divisors, whose sum is σ = 51100532. Its totient is φ = 51100530.

The previous prime is 51100529. The next prime is 51100547. The reversal of 51100531 is 13500115.

It is an a-pointer prime, because the next prime (51100547) can be obtained adding 51100531 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51100531 - 21 = 51100529 is a prime.

It is a super-2 number, since 2×511005312 = 5222528536963922, which contains 22 as substring.

Together with 51100529, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (51100501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550265 + 25550266.

It is an arithmetic number, because the mean of its divisors is an integer number (25550266).

Almost surely, 251100531 is an apocalyptic number.

51100531 is a deficient number, since it is larger than the sum of its proper divisors (1).

51100531 is an equidigital number, since it uses as much as digits as its factorization.

51100531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 16.

The square root of 51100531 is about 7148.4635412094. The cubic root of 51100531 is about 371.0864850698.

Adding to 51100531 its reverse (13500115), we get a palindrome (64600646).

The spelling of 51100531 in words is "fifty-one million, one hundred thousand, five hundred thirty-one".