Base | Representation |
---|---|
bin | 10111001111001110001100… |
… | …11101100100010110011110 |
3 | 20200221011110120121102101212 |
4 | 23213213012131210112132 |
5 | 23144212414210412400 |
6 | 300403134322304422 |
7 | 13522615255346132 |
oct | 1347470635442636 |
9 | 220834416542355 |
10 | 51100555560350 |
11 | 1531169547486a |
12 | 58937687b8112 |
13 | 22689b963758a |
14 | c893cc7ab3c2 |
15 | 5d93992a1335 |
hex | 2e79c676459e |
51100555560350 has 12 divisors (see below), whose sum is σ = 95047033342344. Its totient is φ = 20440222224120.
The previous prime is 51100555560349. The next prime is 51100555560361. The reversal of 51100555560350 is 5306555500115.
It is a super-2 number, since 2×511005555603502 (a number of 28 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 51100555560298 and 51100555560307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 511005555554 + ... + 511005555653.
It is an arithmetic number, because the mean of its divisors is an integer number (7920586111862).
Almost surely, 251100555560350 is an apocalyptic number.
51100555560350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
51100555560350 is a deficient number, since it is larger than the sum of its proper divisors (43946477781994).
51100555560350 is a wasteful number, since it uses less digits than its factorization.
51100555560350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1022011111219 (or 1022011111214 counting only the distinct ones).
The product of its (nonzero) digits is 281250, while the sum is 41.
The spelling of 51100555560350 in words is "fifty-one trillion, one hundred billion, five hundred fifty-five million, five hundred sixty thousand, three hundred fifty".
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