Base | Representation |
---|---|
bin | 1001100001001011… |
… | …00001101101111111 |
3 | 111012010120112121012 |
4 | 10300211201231333 |
5 | 40431142023403 |
6 | 2203023225435 |
7 | 240430141046 |
oct | 46045415577 |
9 | 14163515535 |
10 | 5110111103 |
11 | 2192585119 |
12 | ba744827b |
13 | 6359026a6 |
14 | 36696555d |
15 | 1ed956ed8 |
hex | 130961b7f |
5110111103 has 2 divisors, whose sum is σ = 5110111104. Its totient is φ = 5110111102.
The previous prime is 5110111081. The next prime is 5110111117. The reversal of 5110111103 is 3011110115.
It is an a-pointer prime, because the next prime (5110111117) can be obtained adding 5110111103 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5110111103 - 28 = 5110110847 is a prime.
It is a super-2 number, since 2×51101111032 = 52226470970007753218, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5110111133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555055551 + 2555055552.
It is an arithmetic number, because the mean of its divisors is an integer number (2555055552).
Almost surely, 25110111103 is an apocalyptic number.
5110111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110111103 is an equidigital number, since it uses as much as digits as its factorization.
5110111103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 14.
The square root of 5110111103 is about 71485.0411135085. The cubic root of 5110111103 is about 1722.4374023481.
Adding to 5110111103 its reverse (3011110115), we get a palindrome (8121221218).
The spelling of 5110111103 in words is "five billion, one hundred ten million, one hundred eleven thousand, one hundred three".
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