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5110313350 = 252102206267
BaseRepresentation
bin1001100001001100…
…10011000110000110
3111012010221211000211
410300212103012012
540431220011400
62203031430034
7240431642512
oct46046230606
914163854024
105110313350
11219270306a
12ba752531a
1363597376c
143669b9142
151ed996dba
hex130993186

5110313350 has 12 divisors (see below), whose sum is σ = 9505182924. Its totient is φ = 2044125320.

The previous prime is 5110313333. The next prime is 5110313363. The reversal of 5110313350 is 533130115.

It is a super-2 number, since 2×51103133502 = 52230605070376445000, which contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 51103084 + ... + 51103183.

It is an arithmetic number, because the mean of its divisors is an integer number (792098577).

Almost surely, 25110313350 is an apocalyptic number.

5110313350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

5110313350 is a deficient number, since it is larger than the sum of its proper divisors (4394869574).

5110313350 is a wasteful number, since it uses less digits than its factorization.

5110313350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102206279 (or 102206274 counting only the distinct ones).

The product of its (nonzero) digits is 675, while the sum is 22.

The square root of 5110313350 is about 71486.4557101553. The cubic root of 5110313350 is about 1722.4601254810.

Adding to 5110313350 its reverse (533130115), we get a palindrome (5643443465).

The spelling of 5110313350 in words is "five billion, one hundred ten million, three hundred thirteen thousand, three hundred fifty".

Divisors: 1 2 5 10 25 50 102206267 204412534 511031335 1022062670 2555156675 5110313350