Base | Representation |
---|---|
bin | 1110110111111001000… |
… | …11000110110101110101 |
3 | 1210212002110221112001121 |
4 | 13123330203012311311 |
5 | 31333104024434141 |
6 | 1030434153223541 |
7 | 51631061355643 |
oct | 7337443066565 |
9 | 1725073845047 |
10 | 511043202421 |
11 | 187806623974 |
12 | 83063401bb1 |
13 | 39263cc078b |
14 | 1aa3db3c193 |
15 | d4603a81d1 |
hex | 76fc8c6d75 |
511043202421 has 2 divisors, whose sum is σ = 511043202422. Its totient is φ = 511043202420.
The previous prime is 511043202377. The next prime is 511043202487. The reversal of 511043202421 is 124202340115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 489986000100 + 21057202321 = 699990^2 + 145111^2 .
It is a cyclic number.
It is not a de Polignac number, because 511043202421 - 217 = 511043071349 is a prime.
It is a super-2 number, since 2×5110432024212 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (511043202491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255521601210 + 255521601211.
It is an arithmetic number, because the mean of its divisors is an integer number (255521601211).
Almost surely, 2511043202421 is an apocalyptic number.
It is an amenable number.
511043202421 is a deficient number, since it is larger than the sum of its proper divisors (1).
511043202421 is an equidigital number, since it uses as much as digits as its factorization.
511043202421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 511043202421 its reverse (124202340115), we get a palindrome (635245542536).
The spelling of 511043202421 in words is "five hundred eleven billion, forty-three million, two hundred two thousand, four hundred twenty-one".
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