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51105604325339 is a prime number
BaseRepresentation
bin10111001111010111100110…
…11001000100111111011011
320200221122111102202020221202
423213223303121010333123
523144303234201402324
6300405331315024415
713523154342215444
oct1347536331047733
9220848442666852
1051105604325339
1115313846359713
12589473759b10b
13226931260b395
14c8974b1242cb
155d959263b8ae
hex2e7af3644fdb

51105604325339 has 2 divisors, whose sum is σ = 51105604325340. Its totient is φ = 51105604325338.

The previous prime is 51105604325263. The next prime is 51105604325341. The reversal of 51105604325339 is 93352340650115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51105604325339 - 240 = 50006092697563 is a prime.

It is a super-2 number, since 2×511056043253392 (a number of 28 digits) contains 22 as substring.

Together with 51105604325341, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 51105604325293 and 51105604325302.

It is not a weakly prime, because it can be changed into another prime (51105604325239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25552802162669 + 25552802162670.

It is an arithmetic number, because the mean of its divisors is an integer number (25552802162670).

Almost surely, 251105604325339 is an apocalyptic number.

51105604325339 is a deficient number, since it is larger than the sum of its proper divisors (1).

51105604325339 is an equidigital number, since it uses as much as digits as its factorization.

51105604325339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458000, while the sum is 47.

The spelling of 51105604325339 in words is "fifty-one trillion, one hundred five billion, six hundred four million, three hundred twenty-five thousand, three hundred thirty-nine".