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51105958373 is a prime number
BaseRepresentation
bin101111100110001001…
…110000100111100101
311212220122212200022002
4233212021300213211
51314131111131443
635251110015045
73456311323121
oct574611604745
9155818780262
1051105958373
111a745a87a38
129aa3347485
134a85c28772
14268b580581
1514e1a062b8
hexbe62709e5

51105958373 has 2 divisors, whose sum is σ = 51105958374. Its totient is φ = 51105958372.

The previous prime is 51105958361. The next prime is 51105958469. The reversal of 51105958373 is 37385950115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44443807489 + 6662150884 = 210817^2 + 81622^2 .

It is a cyclic number.

It is not a de Polignac number, because 51105958373 - 24 = 51105958357 is a prime.

It is a super-2 number, since 2×511059583732 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51105958303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25552979186 + 25552979187.

It is an arithmetic number, because the mean of its divisors is an integer number (25552979187).

Almost surely, 251105958373 is an apocalyptic number.

It is an amenable number.

51105958373 is a deficient number, since it is larger than the sum of its proper divisors (1).

51105958373 is an equidigital number, since it uses as much as digits as its factorization.

51105958373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 567000, while the sum is 47.

The spelling of 51105958373 in words is "fifty-one billion, one hundred five million, nine hundred fifty-eight thousand, three hundred seventy-three".