Base | Representation |
---|---|
bin | 100101001011110100000… |
… | …0110010111111100011111 |
3 | 200002120101012112101122112 |
4 | 1022113220012113330133 |
5 | 1132213012141144444 |
6 | 14511440514504235 |
7 | 1035141453045605 |
oct | 112275006277437 |
9 | 20076335471575 |
10 | 5110610099999 |
11 | 16a0441193848 |
12 | 6a6578b9507b |
13 | 2b0c0bab4c91 |
14 | 1394d79c1875 |
15 | 8ce1317e69e |
hex | 4a5e8197f1f |
5110610099999 has 2 divisors, whose sum is σ = 5110610100000. Its totient is φ = 5110610099998.
The previous prime is 5110610099981. The next prime is 5110610100047. The reversal of 5110610099999 is 9999900160115.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5110610099999 - 240 = 4011098472223 is a prime.
It is a super-2 number, since 2×51106100999992 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5110610099099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555305049999 + 2555305050000.
It is an arithmetic number, because the mean of its divisors is an integer number (2555305050000).
Almost surely, 25110610099999 is an apocalyptic number.
5110610099999 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110610099999 is an equidigital number, since it uses as much as digits as its factorization.
5110610099999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1771470, while the sum is 59.
The spelling of 5110610099999 in words is "five trillion, one hundred ten billion, six hundred ten million, ninety-nine thousand, nine hundred ninety-nine".
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