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51110317637 is a prime number
BaseRepresentation
bin101111100110011010…
…011000111001000101
311212220222002011002022
4233212122120321011
51314133220131022
635251343252525
73456363350261
oct574632307105
9155828064068
1051110317637
111a748495135
129aa48aa145
134a86ac3a02
14268bd970a1
1514e20b7c42
hexbe6698e45

51110317637 has 2 divisors, whose sum is σ = 51110317638. Its totient is φ = 51110317636.

The previous prime is 51110317631. The next prime is 51110317639. The reversal of 51110317637 is 73671301115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47216682436 + 3893635201 = 217294^2 + 62399^2 .

It is a cyclic number.

It is not a de Polignac number, because 51110317637 - 226 = 51043208773 is a prime.

It is a super-2 number, since 2×511103176372 (a number of 22 digits) contains 22 as substring.

Together with 51110317639, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 51110317597 and 51110317606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51110317631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25555158818 + 25555158819.

It is an arithmetic number, because the mean of its divisors is an integer number (25555158819).

Almost surely, 251110317637 is an apocalyptic number.

It is an amenable number.

51110317637 is a deficient number, since it is larger than the sum of its proper divisors (1).

51110317637 is an equidigital number, since it uses as much as digits as its factorization.

51110317637 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13230, while the sum is 35.

The spelling of 51110317637 in words is "fifty-one billion, one hundred ten million, three hundred seventeen thousand, six hundred thirty-seven".