Base | Representation |
---|---|
bin | 100101001100000001001… |
… | …0100110101111101000111 |
3 | 200002121111212110201221021 |
4 | 1022120002110311331013 |
5 | 1132214412311204201 |
6 | 14511552313332011 |
7 | 1035155405020213 |
oct | 112300224657507 |
9 | 20077455421837 |
10 | 5111050100551 |
11 | 16a064759a76a |
12 | 6a6680407007 |
13 | 2b0c7bcc0435 |
14 | 13953a1d9943 |
15 | 8ce3bae4ea1 |
hex | 4a602535f47 |
5111050100551 has 2 divisors, whose sum is σ = 5111050100552. Its totient is φ = 5111050100550.
The previous prime is 5111050100537. The next prime is 5111050100567. The reversal of 5111050100551 is 1550010501115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5111050100551 - 27 = 5111050100423 is a prime.
It is a super-2 number, since 2×51110501005512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111050100531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555525050275 + 2555525050276.
It is an arithmetic number, because the mean of its divisors is an integer number (2555525050276).
Almost surely, 25111050100551 is an apocalyptic number.
5111050100551 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111050100551 is an equidigital number, since it uses as much as digits as its factorization.
5111050100551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 625, while the sum is 25.
Adding to 5111050100551 its reverse (1550010501115), we get a palindrome (6661060601666).
The spelling of 5111050100551 in words is "five trillion, one hundred eleven billion, fifty million, one hundred thousand, five hundred fifty-one".
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