Base | Representation |
---|---|
bin | 1110111000000000011… |
… | …11000010010111110001 |
3 | 1210212020210022201010021 |
4 | 13130000033002113301 |
5 | 31333220343100342 |
6 | 1030444243003441 |
7 | 51632442146605 |
oct | 7340017022761 |
9 | 1725223281107 |
10 | 511105050097 |
11 | 187838526a54 |
12 | 83080069581 |
13 | 39273a66735 |
14 | 1aa4803b505 |
15 | d465a23567 |
hex | 77003c25f1 |
511105050097 has 2 divisors, whose sum is σ = 511105050098. Its totient is φ = 511105050096.
The previous prime is 511105050091. The next prime is 511105050101. The reversal of 511105050097 is 790050501115.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 509105082256 + 1999967841 = 713516^2 + 44721^2 .
It is a cyclic number.
It is not a de Polignac number, because 511105050097 - 23 = 511105050089 is a prime.
It is a super-2 number, since 2×5111050500972 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (511105050091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255552525048 + 255552525049.
It is an arithmetic number, because the mean of its divisors is an integer number (255552525049).
Almost surely, 2511105050097 is an apocalyptic number.
It is an amenable number.
511105050097 is a deficient number, since it is larger than the sum of its proper divisors (1).
511105050097 is an equidigital number, since it uses as much as digits as its factorization.
511105050097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7875, while the sum is 34.
The spelling of 511105050097 in words is "five hundred eleven billion, one hundred five million, fifty thousand, ninety-seven".
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