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511111100053 is a prime number
BaseRepresentation
bin1110111000000001001…
…10000111011010010101
31210212021012201002002201
413130000212013122111
531333223420200203
61030445020404501
751632544445141
oct7340046073225
91725235632081
10511111100053
11187840989414
12830820a6731
13392750a43a8
141aa48b74221
15d46631ae1d
hex7700987695

511111100053 has 2 divisors, whose sum is σ = 511111100054. Its totient is φ = 511111100052.

The previous prime is 511111100051. The next prime is 511111100057. The reversal of 511111100053 is 350001111115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 406524833649 + 104586266404 = 637593^2 + 323398^2 .

It is a cyclic number.

It is not a de Polignac number, because 511111100053 - 21 = 511111100051 is a prime.

It is a super-2 number, since 2×5111111000532 (a number of 24 digits) contains 22 as substring.

Together with 511111100051, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 511111100053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511111100051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255555550026 + 255555550027.

It is an arithmetic number, because the mean of its divisors is an integer number (255555550027).

Almost surely, 2511111100053 is an apocalyptic number.

It is an amenable number.

511111100053 is a deficient number, since it is larger than the sum of its proper divisors (1).

511111100053 is an equidigital number, since it uses as much as digits as its factorization.

511111100053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 19.

Adding to 511111100053 its reverse (350001111115), we get a palindrome (861112211168).

The spelling of 511111100053 in words is "five hundred eleven billion, one hundred eleven million, one hundred thousand, fifty-three".