511121053453 has 2 divisors, whose sum is σ = 511121053454. Its totient is φ = 511121053452.

The previous prime is 511121053451. The next prime is 511121053483. The reversal of 511121053453 is 354350121115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 384713784009 + 126407269444 = 620253^2 + 355538^2 .

It is a cyclic number.

It is not a de Polignac number, because 511121053453 - 2¹ = 511121053451 is a prime.

It is a super-2 number, since 2×511121053453² (a number of 24 digits) contains 22 as substring.

Together with 511121053451, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511121053451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255560526726 + 255560526727.

It is an arithmetic number, because the mean of its divisors is an integer number (255560526727).

Almost surely, 2^511121053453 is an apocalyptic number.

It is an amenable number.

511121053453 is a deficient number, since it is larger than the sum of its proper divisors (1).

511121053453 is an equidigital number, since it uses as much as digits as its factorization.

511121053453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 511121053453 its reverse (354350121115), we get a palindrome (865471174568).

The spelling of 511121053453 in words is "five hundred eleven billion, one hundred twenty-one million, fifty-three thousand, four hundred fifty-three".