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51112355500127 is a prime number
BaseRepresentation
bin10111001111100100001011…
…10010110001000001011111
320200222021220221021110201102
423213302011302301001133
523144411101002001002
6300412405244103315
713523513550234665
oct1347620562610137
9220867827243642
1051112355500127
11153166a0202209
125895b00534b3b
132269b4a1c356c
14c89bcb9ccc35
155d983a1a4a02
hex2e7c85cb105f

51112355500127 has 2 divisors, whose sum is σ = 51112355500128. Its totient is φ = 51112355500126.

The previous prime is 51112355500123. The next prime is 51112355500153. The reversal of 51112355500127 is 72100555321115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51112355500127 - 22 = 51112355500123 is a prime.

It is a super-3 number, since 3×511123555001273 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51112355500123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556177750063 + 25556177750064.

It is an arithmetic number, because the mean of its divisors is an integer number (25556177750064).

Almost surely, 251112355500127 is an apocalyptic number.

51112355500127 is a deficient number, since it is larger than the sum of its proper divisors (1).

51112355500127 is an equidigital number, since it uses as much as digits as its factorization.

51112355500127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52500, while the sum is 38.

The spelling of 51112355500127 in words is "fifty-one trillion, one hundred twelve billion, three hundred fifty-five million, five hundred thousand, one hundred twenty-seven".