Base | Representation |
---|---|
bin | 101111100110100010… |
… | …110101011001001101 |
3 | 11212221010020121222110 |
4 | 233212202311121031 |
5 | 1314134302002113 |
6 | 35251502534233 |
7 | 3456421230630 |
oct | 574642653115 |
9 | 155833217873 |
10 | 51112531533 |
11 | 1a7497674a8 |
12 | 9aa5597379 |
13 | 4a873ba5cb |
14 | 268c3b1c17 |
15 | 14e23a3bc3 |
hex | be68b564d |
51112531533 has 32 divisors (see below), whose sum is σ = 79201652992. Its totient is φ = 28714176000.
The previous prime is 51112531531. The next prime is 51112531573. The reversal of 51112531533 is 33513521115.
It is not a de Polignac number, because 51112531533 - 21 = 51112531531 is a prime.
It is a super-2 number, since 2×511125315332 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51112531533.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51112531531) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2928633 + ... + 2946033.
It is an arithmetic number, because the mean of its divisors is an integer number (2475051656).
Almost surely, 251112531533 is an apocalyptic number.
It is an amenable number.
51112531533 is a deficient number, since it is larger than the sum of its proper divisors (28089121459).
51112531533 is a wasteful number, since it uses less digits than its factorization.
51112531533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19765.
The product of its digits is 6750, while the sum is 30.
The spelling of 51112531533 in words is "fifty-one billion, one hundred twelve million, five hundred thirty-one thousand, five hundred thirty-three".
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