5111303 has 2 divisors, whose sum is σ = 5111304. Its totient is φ = 5111302.

The previous prime is 5111299. The next prime is 5111317. The reversal of 5111303 is 3031115.

It is an a-pointer prime, because the next prime (5111317) can be obtained adding 5111303 to its sum of digits (14).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5111303 - 2² = 5111299 is a prime.

It is a super-2 number, since 2×5111303² = 52250836715618, which contains 22 as substring.

It is a Sophie Germain prime.

It is an Ulam number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5311303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555651 + 2555652.

It is an arithmetic number, because the mean of its divisors is an integer number (2555652).

Almost surely, 2^5111303 is an apocalyptic number.

5111303 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111303 is an equidigital number, since it uses as much as digits as its factorization.

5111303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 14.

The square root of 5111303 is about 2260.8190993532. The cubic root of 5111303 is about 172.2571307354.

Adding to 5111303 its reverse (3031115), we get a palindrome (8142418).

The spelling of 5111303 in words is "five million, one hundred eleven thousand, three hundred three".