Base | Representation |
---|---|
bin | 1001100001010100… |
… | …01000001100110111 |
3 | 111012012211211012021 |
4 | 10300222020030313 |
5 | 40431444123203 |
6 | 2203105134011 |
7 | 240443323501 |
oct | 46052101467 |
9 | 14165754167 |
10 | 5111317303 |
11 | 2193229384 |
12 | ba792a307 |
13 | 635c35711 |
14 | 366b9ad71 |
15 | 1edae45bd |
hex | 130a88337 |
5111317303 has 2 divisors, whose sum is σ = 5111317304. Its totient is φ = 5111317302.
The previous prime is 5111317279. The next prime is 5111317333. The reversal of 5111317303 is 3037131115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5111317303 - 229 = 4574446391 is a prime.
It is a super-2 number, since 2×51113173032 = 52251129143894387618, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111317333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555658651 + 2555658652.
It is an arithmetic number, because the mean of its divisors is an integer number (2555658652).
Almost surely, 25111317303 is an apocalyptic number.
5111317303 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111317303 is an equidigital number, since it uses as much as digits as its factorization.
5111317303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 945, while the sum is 25.
The square root of 5111317303 is about 71493.4773458390. The cubic root of 5111317303 is about 1722.5729141147.
Adding to 5111317303 its reverse (3037131115), we get a palindrome (8148448418).
The spelling of 5111317303 in words is "five billion, one hundred eleven million, three hundred seventeen thousand, three hundred three".
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