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5111317303 is a prime number
BaseRepresentation
bin1001100001010100…
…01000001100110111
3111012012211211012021
410300222020030313
540431444123203
62203105134011
7240443323501
oct46052101467
914165754167
105111317303
112193229384
12ba792a307
13635c35711
14366b9ad71
151edae45bd
hex130a88337

5111317303 has 2 divisors, whose sum is σ = 5111317304. Its totient is φ = 5111317302.

The previous prime is 5111317279. The next prime is 5111317333. The reversal of 5111317303 is 3037131115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5111317303 - 229 = 4574446391 is a prime.

It is a super-2 number, since 2×51113173032 = 52251129143894387618, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5111317333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555658651 + 2555658652.

It is an arithmetic number, because the mean of its divisors is an integer number (2555658652).

Almost surely, 25111317303 is an apocalyptic number.

5111317303 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111317303 is an equidigital number, since it uses as much as digits as its factorization.

5111317303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 945, while the sum is 25.

The square root of 5111317303 is about 71493.4773458390. The cubic root of 5111317303 is about 1722.5729141147.

Adding to 5111317303 its reverse (3037131115), we get a palindrome (8148448418).

The spelling of 5111317303 in words is "five billion, one hundred eleven million, three hundred seventeen thousand, three hundred three".