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5111322550 = 252102226451
BaseRepresentation
bin1001100001010100…
…01001011110110110
3111012012212002101121
410300222021132312
540431444310200
62203105214154
7240443345005
oct46052113666
914165762347
105111322550
112193232314
12ba793135a
13635c37c19
14366b9cc3c
151edae5e1a
hex130a897b6

5111322550 has 12 divisors (see below), whose sum is σ = 9507060036. Its totient is φ = 2044529000.

The previous prime is 5111322539. The next prime is 5111322569. The reversal of 5111322550 is 552231115.

It is a super-2 number, since 2×51113225502 = 52251236420277005000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 51113176 + ... + 51113275.

It is an arithmetic number, because the mean of its divisors is an integer number (792255003).

Almost surely, 25111322550 is an apocalyptic number.

5111322550 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

5111322550 is a deficient number, since it is larger than the sum of its proper divisors (4395737486).

5111322550 is a wasteful number, since it uses less digits than its factorization.

5111322550 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102226463 (or 102226458 counting only the distinct ones).

The product of its (nonzero) digits is 1500, while the sum is 25.

The square root of 5111322550 is about 71493.5140414849. The cubic root of 5111322550 is about 1722.5735035476.

Adding to 5111322550 its reverse (552231115), we get a palindrome (5663553665).

The spelling of 5111322550 in words is "five billion, one hundred eleven million, three hundred twenty-two thousand, five hundred fifty".

Divisors: 1 2 5 10 25 50 102226451 204452902 511132255 1022264510 2555661275 5111322550