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5111331550111 is a prime number
BaseRepresentation
bin100101001100001001100…
…0110011111001110011111
3200002122020111001212011001
41022120103012133032133
51132221001334100421
614512040250011131
71035165363215653
oct112302306371637
920078214055131
105111331550111
1116a0781453a06
126a673a716aa7
132b0cc53c4837
14139565740a63
158ce5668c691
hex4a61319f39f

5111331550111 has 2 divisors, whose sum is σ = 5111331550112. Its totient is φ = 5111331550110.

The previous prime is 5111331550103. The next prime is 5111331550147. The reversal of 5111331550111 is 1110551331115.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5111331550111 - 23 = 5111331550103 is a prime.

It is a super-2 number, since 2×51113315501112 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5111331550111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5111331550181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555665775055 + 2555665775056.

It is an arithmetic number, because the mean of its divisors is an integer number (2555665775056).

Almost surely, 25111331550111 is an apocalyptic number.

5111331550111 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111331550111 is an equidigital number, since it uses as much as digits as its factorization.

5111331550111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1125, while the sum is 28.

Adding to 5111331550111 its reverse (1110551331115), we get a palindrome (6221882881226).

The spelling of 5111331550111 in words is "five trillion, one hundred eleven billion, three hundred thirty-one million, five hundred fifty thousand, one hundred eleven".