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511201004213 is a prime number
BaseRepresentation
bin1110111000001011111…
…01000100101010110101
31210212111110212200102102
413130011331010222311
531333414424113323
61030501551351445
751635015561324
oct7340575045265
91725443780372
10511201004213
11187887704779
12830a8222585
133928a8c1813
141aa56a980bb
15d46e179328
hex7705f44ab5

511201004213 has 2 divisors, whose sum is σ = 511201004214. Its totient is φ = 511201004212.

The previous prime is 511201004207. The next prime is 511201004233. The reversal of 511201004213 is 312400102115.

It is an a-pointer prime, because the next prime (511201004233) can be obtained adding 511201004213 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 329961782929 + 181239221284 = 574423^2 + 425722^2 .

It is a cyclic number.

It is not a de Polignac number, because 511201004213 - 230 = 510127262389 is a prime.

It is a super-2 number, since 2×5112010042132 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511201004233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255600502106 + 255600502107.

It is an arithmetic number, because the mean of its divisors is an integer number (255600502107).

Almost surely, 2511201004213 is an apocalyptic number.

It is an amenable number.

511201004213 is a deficient number, since it is larger than the sum of its proper divisors (1).

511201004213 is an equidigital number, since it uses as much as digits as its factorization.

511201004213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 511201004213 its reverse (312400102115), we get a palindrome (823601106328).

The spelling of 511201004213 in words is "five hundred eleven billion, two hundred one million, four thousand, two hundred thirteen".