511202604641 has 2 divisors, whose sum is σ = 511202604642. Its totient is φ = 511202604640.

The previous prime is 511202604611. The next prime is 511202604643. The reversal of 511202604641 is 146406202115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 482879061025 + 28323543616 = 694895^2 + 168296^2 .

It is a cyclic number.

It is not a de Polignac number, because 511202604641 - 2¹⁴ = 511202588257 is a prime.

It is a super-2 number, since 2×511202604641² (a number of 24 digits) contains 22 as substring.

Together with 511202604643, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 511202604598 and 511202604607.

It is not a weakly prime, because it can be changed into another prime (511202604643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255601302320 + 255601302321.

It is an arithmetic number, because the mean of its divisors is an integer number (255601302321).

Almost surely, 2^511202604641 is an apocalyptic number.

It is an amenable number.

511202604641 is a deficient number, since it is larger than the sum of its proper divisors (1).

511202604641 is an equidigital number, since it uses as much as digits as its factorization.

511202604641 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 511202604641 its reverse (146406202115), we get a palindrome (657608806756).

The spelling of 511202604641 in words is "five hundred eleven billion, two hundred two million, six hundred four thousand, six hundred forty-one".