511214471 has 2 divisors, whose sum is σ = 511214472. Its totient is φ = 511214470.

The previous prime is 511214453. The next prime is 511214477. The reversal of 511214471 is 174412115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 511214471 - 2¹⁴ = 511198087 is a prime.

It is a super-3 number, since 3×511214471³ (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 511214471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511214477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255607235 + 255607236.

It is an arithmetic number, because the mean of its divisors is an integer number (255607236).

Almost surely, 2^511214471 is an apocalyptic number.

511214471 is a deficient number, since it is larger than the sum of its proper divisors (1).

511214471 is an equidigital number, since it uses as much as digits as its factorization.

511214471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1120, while the sum is 26.

The square root of 511214471 is about 22610.0524324912. The cubic root of 511214471 is about 799.5906609001.

Adding to 511214471 its reverse (174412115), we get a palindrome (685626586).

The spelling of 511214471 in words is "five hundred eleven million, two hundred fourteen thousand, four hundred seventy-one".