Base | Representation |
---|---|
bin | 100101001100100011110… |
… | …1000111101100010111001 |
3 | 200002201111220200021102001 |
4 | 1022121013220331202321 |
5 | 1132224303012034200 |
6 | 14512303534341001 |
7 | 1035226255354534 |
oct | 112310750754271 |
9 | 20081456607361 |
10 | 5112213002425 |
11 | 16a1093a680a1 |
12 | 6a694595a761 |
13 | 2b1105bc5b59 |
14 | 13960a82da1b |
15 | 8cea8c5376a |
hex | 4a647a3d8b9 |
5112213002425 has 24 divisors (see below), whose sum is σ = 6519162161600. Its totient is φ = 3974585630400.
The previous prime is 5112213002423. The next prime is 5112213002441. The reversal of 5112213002425 is 5242003122115.
It is a happy number.
It is not a de Polignac number, because 5112213002425 - 21 = 5112213002423 is a prime.
It is a super-2 number, since 2×51122130024252 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112213002393 and 5112213002402.
It is not an unprimeable number, because it can be changed into a prime (5112213002423) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11734686 + ... + 12162535.
Almost surely, 25112213002425 is an apocalyptic number.
It is an amenable number.
5112213002425 is a deficient number, since it is larger than the sum of its proper divisors (1406949159175).
5112213002425 is a wasteful number, since it uses less digits than its factorization.
5112213002425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23897473 (or 23897468 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 28.
The spelling of 5112213002425 in words is "five trillion, one hundred twelve billion, two hundred thirteen million, two thousand, four hundred twenty-five".
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