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51132113189 is a prime number
BaseRepresentation
bin101111100111101101…
…100010000100100101
311212222111002110221222
4233213231202010211
51314204310110224
635253442350125
73460046535203
oct574755420445
9155874073858
1051132113189
111a759821493
129ab005b345
134a8b4854a1
142690c2c073
1514e3e70b5e
hexbe7b62125

51132113189 has 2 divisors, whose sum is σ = 51132113190. Its totient is φ = 51132113188.

The previous prime is 51132113183. The next prime is 51132113237. The reversal of 51132113189 is 98131123115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37117104964 + 14015008225 = 192658^2 + 118385^2 .

It is a cyclic number.

It is not a de Polignac number, because 51132113189 - 220 = 51131064613 is a prime.

It is a super-2 number, since 2×511321131892 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51132113183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25566056594 + 25566056595.

It is an arithmetic number, because the mean of its divisors is an integer number (25566056595).

Almost surely, 251132113189 is an apocalyptic number.

It is an amenable number.

51132113189 is a deficient number, since it is larger than the sum of its proper divisors (1).

51132113189 is an equidigital number, since it uses as much as digits as its factorization.

51132113189 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 35.

The spelling of 51132113189 in words is "fifty-one billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred eighty-nine".