Base | Representation |
---|---|
bin | 101111100111101110… |
… | …110100100111100100 |
3 | 11212222111201122202121 |
4 | 233213232310213210 |
5 | 1314204401420200 |
6 | 35253453515324 |
7 | 3460052444020 |
oct | 574756644744 |
9 | 155874648677 |
10 | 51132451300 |
11 | 1a759a32517 |
12 | 9ab01a2b44 |
13 | 4a8b573358 |
14 | 2690cb9380 |
15 | 14e3edae1a |
hex | be7bb49e4 |
51132451300 has 36 divisors (see below), whose sum is σ = 126808480960. Its totient is φ = 17531125920.
The previous prime is 51132451289. The next prime is 51132451309. The reversal of 51132451300 is 315423115.
It is a happy number.
It is a super-2 number, since 2×511324513002 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (51132451309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 36522480 + ... + 36523879.
Almost surely, 251132451300 is an apocalyptic number.
51132451300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51132451300 is an abundant number, since it is smaller than the sum of its proper divisors (75676029660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51132451300 is a wasteful number, since it uses less digits than its factorization.
51132451300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73046380 (or 73046373 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 51132451300 its reverse (315423115), we get a palindrome (51447874415).
The spelling of 51132451300 in words is "fifty-one billion, one hundred thirty-two million, four hundred fifty-one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 1.046 sec. • engine limits •