Search a number
-
+
5113300597 is a prime number
BaseRepresentation
bin1001100001100011…
…01100011001110101
3111012100120120202121
410300301230121311
540433001104342
62203215435541
7240466223626
oct46061543165
914170516677
105113300597
112194363469
12ba8525bb1
1363647b372
14367155a4d
151edd87067
hex130c6c675

5113300597 has 2 divisors, whose sum is σ = 5113300598. Its totient is φ = 5113300596.

The previous prime is 5113300567. The next prime is 5113300603. The reversal of 5113300597 is 7950033115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4644967716 + 468332881 = 68154^2 + 21641^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5113300597 is a prime.

It is a super-2 number, since 2×51133005972 = 52291685990561112818, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113300567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556650298 + 2556650299.

It is an arithmetic number, because the mean of its divisors is an integer number (2556650299).

Almost surely, 25113300597 is an apocalyptic number.

It is an amenable number.

5113300597 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113300597 is an equidigital number, since it uses as much as digits as its factorization.

5113300597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14175, while the sum is 34.

The square root of 5113300597 is about 71507.3464547525. The cubic root of 5113300597 is about 1722.7956829591.

The spelling of 5113300597 in words is "five billion, one hundred thirteen million, three hundred thousand, five hundred ninety-seven".