Base | Representation |
---|---|
bin | 10111010000011100110101… |
… | …01111010111000100100000 |
3 | 20201002012102200201111222122 |
4 | 23220032122233113010200 |
5 | 23200410344023400000 |
6 | 300434355344523412 |
7 | 13525641362536361 |
oct | 1350163257270440 |
9 | 221065380644878 |
10 | 51142771700000 |
11 | 15328589376382 |
12 | 589b98a920568 |
13 | 226c98687c776 |
14 | c8b475417b68 |
15 | 5da51a5e2085 |
hex | 2e839abd7120 |
51142771700000 has 144 divisors (see below), whose sum is σ = 126964864431720. Its totient is φ = 20276067840000.
The previous prime is 51142771699973. The next prime is 51142771700039. The reversal of 51142771700000 is 717724115.
It can be written as a sum of positive squares in 12 ways, for example, as 36890123228176 + 14252648471824 = 6073724^2 + 3775268^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9037046 + ... + 13562954.
Almost surely, 251142771700000 is an apocalyptic number.
51142771700000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 51142771700000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (63482432215860).
51142771700000 is an abundant number, since it is smaller than the sum of its proper divisors (75822092731720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51142771700000 is an equidigital number, since it uses as much as digits as its factorization.
51142771700000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4526057 (or 4526029 counting only the distinct ones).
The product of its (nonzero) digits is 13720, while the sum is 35.
The spelling of 51142771700000 in words is "fifty-one trillion, one hundred forty-two billion, seven hundred seventy-one million, seven hundred thousand".
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