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5114312107 is a prime number
BaseRepresentation
bin1001100001101011…
…00011010110101011
3111012102110222021221
410300311203112223
540433230441412
62203253242511
7240510635632
oct46065432653
914172428257
105114312107
112194994423
12ba8933437
136367438a8
1436733a519
151eded6b07
hex130d635ab

5114312107 has 2 divisors, whose sum is σ = 5114312108. Its totient is φ = 5114312106.

The previous prime is 5114312069. The next prime is 5114312111. The reversal of 5114312107 is 7012134115.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5114312107 is a prime.

It is not a weakly prime, because it can be changed into another prime (5114312807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557156053 + 2557156054.

It is an arithmetic number, because the mean of its divisors is an integer number (2557156054).

Almost surely, 25114312107 is an apocalyptic number.

5114312107 is a deficient number, since it is larger than the sum of its proper divisors (1).

5114312107 is an equidigital number, since it uses as much as digits as its factorization.

5114312107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

The square root of 5114312107 is about 71514.4188747975. The cubic root of 5114312107 is about 1722.9092762656.

The spelling of 5114312107 in words is "five billion, one hundred fourteen million, three hundred twelve thousand, one hundred seven".