Base | Representation |
---|---|
bin | 1001100001101011… |
… | …00011010110101111 |
3 | 111012102110222022002 |
4 | 10300311203112233 |
5 | 40433230441421 |
6 | 2203253242515 |
7 | 240510635636 |
oct | 46065432657 |
9 | 14172428262 |
10 | 5114312111 |
11 | 2194994427 |
12 | ba893343b |
13 | 6367438ac |
14 | 36733a51d |
15 | 1eded6b0b |
hex | 130d635af |
5114312111 has 2 divisors, whose sum is σ = 5114312112. Its totient is φ = 5114312110.
The previous prime is 5114312107. The next prime is 5114312143. The reversal of 5114312111 is 1112134115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5114312111 - 22 = 5114312107 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5114312171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557156055 + 2557156056.
It is an arithmetic number, because the mean of its divisors is an integer number (2557156056).
Almost surely, 25114312111 is an apocalyptic number.
5114312111 is a deficient number, since it is larger than the sum of its proper divisors (1).
5114312111 is an equidigital number, since it uses as much as digits as its factorization.
5114312111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 120, while the sum is 20.
The square root of 5114312111 is about 71514.4189027639. The cubic root of 5114312111 is about 1722.9092767147.
Adding to 5114312111 its reverse (1112134115), we get a palindrome (6226446226).
The spelling of 5114312111 in words is "five billion, one hundred fourteen million, three hundred twelve thousand, one hundred eleven".
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