Base | Representation |
---|---|
bin | 100101001101100010100… |
… | …1111010111100000110101 |
3 | 200002220221202210010121011 |
4 | 1022123011033113200311 |
5 | 1132243111434103021 |
6 | 14513253011352221 |
7 | 1035332423421565 |
oct | 112330517274065 |
9 | 20086852703534 |
10 | 5114320222261 |
11 | 16a1a75487598 |
12 | 6a72335b2671 |
13 | 2b1380640cb3 |
14 | 13976a638da5 |
15 | 8d07dc44de1 |
hex | 4a6c53d7835 |
5114320222261 has 2 divisors, whose sum is σ = 5114320222262. Its totient is φ = 5114320222260.
The previous prime is 5114320222169. The next prime is 5114320222303. The reversal of 5114320222261 is 1622220234115.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3464508419761 + 1649811802500 = 1861319^2 + 1284450^2 .
It is a cyclic number.
It is not a de Polignac number, because 5114320222261 - 219 = 5114319697973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5114320222961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557160111130 + 2557160111131.
It is an arithmetic number, because the mean of its divisors is an integer number (2557160111131).
Almost surely, 25114320222261 is an apocalyptic number.
It is an amenable number.
5114320222261 is a deficient number, since it is larger than the sum of its proper divisors (1).
5114320222261 is an equidigital number, since it uses as much as digits as its factorization.
5114320222261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 5114320222261 its reverse (1622220234115), we get a palindrome (6736540456376).
The spelling of 5114320222261 in words is "five trillion, one hundred fourteen billion, three hundred twenty million, two hundred twenty-two thousand, two hundred sixty-one".
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