Base | Representation |
---|---|
bin | 1001100001101100… |
… | …00011100101010101 |
3 | 111012102201200101012 |
4 | 10300312003211111 |
5 | 40433244202432 |
6 | 2203300142005 |
7 | 240512025536 |
oct | 46066034525 |
9 | 14172650335 |
10 | 5114444117 |
11 | 2194a74622 |
12 | ba8997905 |
13 | 63678b9c3 |
14 | 36737268d |
15 | 1ee010cb2 |
hex | 130d83955 |
5114444117 has 2 divisors, whose sum is σ = 5114444118. Its totient is φ = 5114444116.
The previous prime is 5114444107. The next prime is 5114444171. The reversal of 5114444117 is 7114444115.
Together with next prime (5114444171) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4717079761 + 397364356 = 68681^2 + 19934^2 .
It is a cyclic number.
It is not a de Polignac number, because 5114444117 - 218 = 5114181973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5114444107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557222058 + 2557222059.
It is an arithmetic number, because the mean of its divisors is an integer number (2557222059).
Almost surely, 25114444117 is an apocalyptic number.
It is an amenable number.
5114444117 is a deficient number, since it is larger than the sum of its proper divisors (1).
5114444117 is an equidigital number, since it uses as much as digits as its factorization.
5114444117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8960, while the sum is 32.
The square root of 5114444117 is about 71515.3418295683. The cubic root of 5114444117 is about 1722.9240999794.
The spelling of 5114444117 in words is "five billion, one hundred fourteen million, four hundred forty-four thousand, one hundred seventeen".
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