Base | Representation |
---|---|
bin | 101111101000101000… |
… | …011001011111011111 |
3 | 11220000120010110210121 |
4 | 233220220121133133 |
5 | 1314222232411133 |
6 | 35255153215411 |
7 | 3460324645444 |
oct | 575050313737 |
9 | 156016113717 |
10 | 51147544543 |
11 | 1a767501277 |
12 | 9ab5261567 |
13 | 4a91729274 |
14 | 2692cc79cb |
15 | 14e54bd02d |
hex | be8a197df |
51147544543 has 2 divisors, whose sum is σ = 51147544544. Its totient is φ = 51147544542.
The previous prime is 51147544541. The next prime is 51147544561. The reversal of 51147544543 is 34544574115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51147544543 - 21 = 51147544541 is a prime.
Together with 51147544541, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 51147544543.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51147544541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25573772271 + 25573772272.
It is an arithmetic number, because the mean of its divisors is an integer number (25573772272).
Almost surely, 251147544543 is an apocalyptic number.
51147544543 is a deficient number, since it is larger than the sum of its proper divisors (1).
51147544543 is an equidigital number, since it uses as much as digits as its factorization.
51147544543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 672000, while the sum is 43.
The spelling of 51147544543 in words is "fifty-one billion, one hundred forty-seven million, five hundred forty-four thousand, five hundred forty-three".
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