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51151512262133 is a prime number
BaseRepresentation
bin10111010000101101000111…
…01101111101010111110101
320201010000222211122002011002
423220112203231331113311
523201031244114342013
6300442402541253045
713526401105226663
oct1350264355752765
9221100884562132
1051151512262133
1115331264178048
1258a1609b64185
13227074a66461a
14c8ba641b7c33
155da87cb23358
hex2e85a3b7d5f5

51151512262133 has 2 divisors, whose sum is σ = 51151512262134. Its totient is φ = 51151512262132.

The previous prime is 51151512262061. The next prime is 51151512262211. The reversal of 51151512262133 is 33126221515115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38692356021124 + 12459156241009 = 6220318^2 + 3529753^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51151512262133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51151512282133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25575756131066 + 25575756131067.

It is an arithmetic number, because the mean of its divisors is an integer number (25575756131067).

Almost surely, 251151512262133 is an apocalyptic number.

It is an amenable number.

51151512262133 is a deficient number, since it is larger than the sum of its proper divisors (1).

51151512262133 is an equidigital number, since it uses as much as digits as its factorization.

51151512262133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 54000, while the sum is 38.

Adding to 51151512262133 its reverse (33126221515115), we get a palindrome (84277733777248).

The spelling of 51151512262133 in words is "fifty-one trillion, one hundred fifty-one billion, five hundred twelve million, two hundred sixty-two thousand, one hundred thirty-three".