Base | Representation |
---|---|
bin | 101111101010000010… |
… | …011101110001100111 |
3 | 11220002012120000022201 |
4 | 233222002131301213 |
5 | 1314244303430142 |
6 | 35301355235331 |
7 | 3461032432645 |
oct | 575202356147 |
9 | 156065500281 |
10 | 51171155047 |
11 | 1a779868191 |
12 | 9b01148b47 |
13 | 4a965a4b8c |
14 | 26960b2195 |
15 | 14e75d3ab7 |
hex | bea09dc67 |
51171155047 has 2 divisors, whose sum is σ = 51171155048. Its totient is φ = 51171155046.
The previous prime is 51171155041. The next prime is 51171155059. The reversal of 51171155047 is 74055117115.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51171155047 - 227 = 51036937319 is a prime.
It is a super-2 number, since 2×511711550472 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51171154997 and 51171155015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51171155041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25585577523 + 25585577524.
It is an arithmetic number, because the mean of its divisors is an integer number (25585577524).
Almost surely, 251171155047 is an apocalyptic number.
51171155047 is a deficient number, since it is larger than the sum of its proper divisors (1).
51171155047 is an equidigital number, since it uses as much as digits as its factorization.
51171155047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24500, while the sum is 37.
The spelling of 51171155047 in words is "fifty-one billion, one hundred seventy-one million, one hundred fifty-five thousand, forty-seven".
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