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51180857449919 is a prime number
BaseRepresentation
bin10111010001100011110001…
…10100111101110110111111
320201012211201221210002000222
423220301320310331312333
523202021344001344134
6300504054502411555
713531460234220221
oct1350617064756677
9221184657702028
1051180857449919
1115342752825a5a
1258a7239730bbb
13227344617c272
14c8d24968c411
155db4e9003a2e
hex2e8c78d3ddbf

51180857449919 has 2 divisors, whose sum is σ = 51180857449920. Its totient is φ = 51180857449918.

The previous prime is 51180857449907. The next prime is 51180857449921. The reversal of 51180857449919 is 91994475808115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51180857449919 - 28 = 51180857449663 is a prime.

It is a super-2 number, since 2×511808574499192 (a number of 28 digits) contains 22 as substring.

Together with 51180857449921, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51180857449999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25590428724959 + 25590428724960.

It is an arithmetic number, because the mean of its divisors is an integer number (25590428724960).

Almost surely, 251180857449919 is an apocalyptic number.

51180857449919 is a deficient number, since it is larger than the sum of its proper divisors (1).

51180857449919 is an equidigital number, since it uses as much as digits as its factorization.

51180857449919 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 130636800, while the sum is 71.

The spelling of 51180857449919 in words is "fifty-one trillion, one hundred eighty billion, eight hundred fifty-seven million, four hundred forty-nine thousand, nine hundred nineteen".