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512004512512397 is a prime number
BaseRepresentation
bin111010001101010100101011…
…1000101110111100110001101
32111010212011010210202010111202
41310122221113011313212031
51014102140220200344042
65012535343110355245
7212563051056623132
oct16432512705674615
92433764123663452
10512004512512397
1113915a992423a63
1249511aa335bb25
1318c8ca83c1b348
149061217480589
153e2d62ba7e632
hex1d1aa5717798d

512004512512397 has 2 divisors, whose sum is σ = 512004512512398. Its totient is φ = 512004512512396.

The previous prime is 512004512512387. The next prime is 512004512512411. The reversal of 512004512512397 is 793215215400215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 454083112719076 + 57921399793321 = 21309226^2 + 7610611^2 .

It is a cyclic number.

It is not a de Polignac number, because 512004512512397 - 230 = 512003438770573 is a prime.

It is a super-2 number, since 2×5120045125123972 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (512004512512307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256002256256198 + 256002256256199.

It is an arithmetic number, because the mean of its divisors is an integer number (256002256256199).

Almost surely, 2512004512512397 is an apocalyptic number.

It is an amenable number.

512004512512397 is a deficient number, since it is larger than the sum of its proper divisors (1).

512004512512397 is an equidigital number, since it uses as much as digits as its factorization.

512004512512397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756000, while the sum is 47.

The spelling of 512004512512397 in words is "five hundred twelve trillion, four billion, five hundred twelve million, five hundred twelve thousand, three hundred ninety-seven".