Base | Representation |
---|---|
bin | 100101010000001111001… |
… | …1001111100100100101101 |
3 | 200010110220100101222111112 |
4 | 1022200132121330210231 |
5 | 1132341441422310041 |
6 | 14520051355001405 |
7 | 1035626061364301 |
oct | 112403631744455 |
9 | 20113810358445 |
10 | 5120111135021 |
11 | 16a4477289003 |
12 | 6a838aa39265 |
13 | 2b1a942c04ac |
14 | 139b5977bd01 |
15 | 8d2bc32adeb |
hex | 4a81e67c92d |
5120111135021 has 2 divisors, whose sum is σ = 5120111135022. Its totient is φ = 5120111135020.
The previous prime is 5120111134981. The next prime is 5120111135023. The reversal of 5120111135021 is 1205311110215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3598191672100 + 1521919462921 = 1896890^2 + 1233661^2 .
It is a cyclic number.
It is not a de Polignac number, because 5120111135021 - 214 = 5120111118637 is a prime.
Together with 5120111135023, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5120111135023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560055567510 + 2560055567511.
It is an arithmetic number, because the mean of its divisors is an integer number (2560055567511).
Almost surely, 25120111135021 is an apocalyptic number.
It is an amenable number.
5120111135021 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120111135021 is an equidigital number, since it uses as much as digits as its factorization.
5120111135021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 300, while the sum is 23.
Adding to 5120111135021 its reverse (1205311110215), we get a palindrome (6325422245236).
The spelling of 5120111135021 in words is "five trillion, one hundred twenty billion, one hundred eleven million, one hundred thirty-five thousand, twenty-one".
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